Math, asked by faisal186, 1 year ago

A circular tunnel of diameter 2m and length 1.4km is dig out find the cost of plastering it at ₹150 per 100m square.

Answers

Answered by chiranjeev31
5
Diameter of circular tunnel = 2m
Radius of the circular tunnel = 1m
Height of the circular tunnel = 1.4 km
=1400 m

Area to be plastered = (2×22/7×1×1400)+(22/7×1×1)
=8800+22/7
=(61600+22)/7
=61622/7 m square

Cost of plastering 1 m Sq. = 150 per m Sq.
Cost of plastering 61622/7 m Sq. = 150×(61622/7)
=1320471.42 (approx.)

Answered by Anonymous
22

\Large{\textbf{\underline{\underline{According\:to\:the\:Question}}}}

\textbf{\underline{Shape\;of\;Circular\;tunnel=Cylinder}}

Given:

D of tunnel = 2 m

{\boxed{\sf\:{radius=\dfrac{Diameter}{2}}}}

{\boxed{\sf\:{r=\dfrac{2}{2}}}}

r = 1m

{\boxed{\sf\:{H\;of\;Tunnel}}}

= 1.4 km

\textbf{\underline{Convert\;it\;into\;m}}

= 1.4 × 1000

= 1400 m

{\boxed{\sf\:{CSA\;of\;Cylinder=2\pi rh}}}

\tt{\rightarrow 2\times\dfrac{22}{7}\times 1\times 1400}

2 × 22 × 200 = 44 × 200

= 8800 m²

\textbf{\underline{Cost\;of\;Plastering}}

= CSA of Cylinder × Rate

\tt{\rightarrow\dfrac{8800\times 150}{100}}

= 88 × 150

= ₹ 13200

Therefore,

{\boxed{\sf\:{Cost\;of\; Plastering\;is 13200}}}

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