Question

prove that : 1-sintheta/1+sintheta = (sectheta - tantheta)²

Answer 1

the answer u r searching for is here....

LHS=1−sinθ/1+sinθ

=1−sinθ/1+sinθ×1−sinθ/1−sinθ

=(1−sinθ)^2/1−sinθ^2

=(1−sinθ)^2/cosθ^2 as 1-sinθ^2=cosθ^2

=(1−sinθ/cosθ)^2

=(1/cosθ−sinθ/cosθ)^2

=(secθ−tanθ)^2=RHS as secθ=1/cosθ and tan theta = sin / cos


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