a circular wire having radius 56 cm is cut and and bent to form a rectangle. the sides of the rectangle are in the ratio of 8:7 . what is the length of the smaller side of the rectangle?
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if radius is 56 cm. then circumference is 352cm.
so the lenth of wire will be 352cm.
perimeter of rectangle = lenth of wire
perimeter of rectangle = 352 cm
let the HCF= x
ATQ
2(8x+7x)=352
15x=352÷2
15x=176
x=176÷15
x=11.73cm
lenth of smaller side=82.13cm
so the lenth of wire will be 352cm.
perimeter of rectangle = lenth of wire
perimeter of rectangle = 352 cm
let the HCF= x
ATQ
2(8x+7x)=352
15x=352÷2
15x=176
x=176÷15
x=11.73cm
lenth of smaller side=82.13cm
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