Question

A circular wire of diameter 42 cm is folded in the
shape of a rectangle whose sides are in the ratio
6: 5. Find the area enclosed by the rectangle.
22
(Take =)
7 1) 540 cm 2)1080 cm 3)2160 cm 4) 4320cm ​

Answer 1

$\Large{\red{\underline{\underline{\tt{AnSweR:}}}}}$

Let the sides of the rectangle be 6x cm and 5x cm.

Perimeter of the rectangle = Circumference of Circle

⇒2(6x+5x)=2×722×21

⇒22x=132

⇒x=6

∴ The sides of the rectangle are 36cm and 30cm.

∴ Area of the rectangle =36×30=1080cm2

Answer 2

$\large \tt \pink {ANSWER...}$

Let the sides of the rectangle be 6x cm and 5x cm.

Perimeter of the rectangle = Circumference of Circle

⇒2(6x+5x)=2×722×21

⇒22x=132

⇒x=6

∴ The sides of the rectangle are 36cm and 30cm.

∴ Area of the rectangle =36×30=1080cm2