Math, asked by nanimoshenallam, 2 months ago

a watch which gains uniformly, is 6 min.slow at 8 o'clock in the morning sunday and it is 6 min. 48 sec. fast at 8 p.m. on following sunday. when was it correct?

a) at 20 min. past 7 p.m. on wednesday.

b) at 35 min. past 7 p.m. on wednesday.

c) at 50 min. past 7 p.m. on wednesday.

d) at 24 min. past 7 p.m. on wednesday.

Answers

Answered by satyajeetmalla004
1

Answer:

Step-by-step explanation:

This sunday morning at 8:00 AM, the watch is 5 min. Slow, and the next sunday at 8:00PM it becomes 5 min 48 sec fast. The watch gains 5+54860 min in a time of (7×24)+12 = 180 hours. To show the correct time, it has to gain 5 min.

545min→180hours

5min ->(5542×180)

8313hrs = 72hrs + 1113hrs = 3days +11hrs + 20min

correct time is wednesday at 7:20 PM

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