Question

A circular wire of radius 2.5cm is cut and bent so as to lie along the circumference of a hoop whose radius is 1m 29cm.find in degrees the angle which is subtended at the centre of the hoop.

Answer 1

In order to calculate the angle formed at the center of the hoop, we use this formula:

S/Circumference = ∅/360 where S will be the length of the circular wire and Circumference will be that of the hoop.

Lets calculate S using the formula 2 x Pi x r; where r is the radius of the circular wire. So we have S = 2 x (22/7) x 2.5

Circumference of the Hoop = 2 x (22/7) x 129

Using the formula to find the angle, we have
[2 x (22/7) x 2.5] / [2 x (22/7) x 129] = ∅/360

Upon solving this would give you ∅ = (2.5/129) × 360 = 6.97°

Answer 2

Answer:

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Step-by-step explanation:

To calculate the angle formed at the center of the hoop, we use this formula:

S/Circumference = ∅/360

Where S will be the length of the circular wire and Circumference will be that of the hoop.

calculate S using the formula 2 x Pi x r;

Where r is the radius of the circular wire. So we have S = 2 x (22/7) x 2.5

Circumference of the Hoop = 2 x (22/7) x 129

Using the formula to find the angle, we have

[2 x (22/7) x 2.5] / [2 x (22/7) x 129] = ∅/360

Upon solving this would give you ∅ = (2.5/129) × 360 = 6.97°