Suppose 1kg ball is coming with speed 20m/s and a batsman deflects the ball with an angle 60degree. Calculate the impulse imparted by the ball if Initial and final velocity of ball are same.
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m = 1 kg
v = 20 m/s
angle = 60 deg of deflection.
angle between velocity and the normal to the bat at collision point = 30 deg.
change in momentum = impulse = 2 m v cos 30 = 2 * 1 * 20 * √3/2
= 20√3 kg-m/sec
v = 20 m/s
angle = 60 deg of deflection.
angle between velocity and the normal to the bat at collision point = 30 deg.
change in momentum = impulse = 2 m v cos 30 = 2 * 1 * 20 * √3/2
= 20√3 kg-m/sec
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