a circular wire of radius 3 cm is cut and bent so as to lie along the circumference of a hoop whose radius is 48 CM the angle in grades which substandard at the centre of the hoop
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Circumference of first wire = 6π cm
Circumference of second wire = 96π cm
Let angle subtented be ∆
Thus (6π/96π) = ∆/2π
∆ = π/8 radian = 22.5 degrees
360 degree = 400 grads.
1 degree = (10/9) grads.
22.5 degrees = 25 grads
Circumference of second wire = 96π cm
Let angle subtented be ∆
Thus (6π/96π) = ∆/2π
∆ = π/8 radian = 22.5 degrees
360 degree = 400 grads.
1 degree = (10/9) grads.
22.5 degrees = 25 grads
Anandmaurya:
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