Question

A circular wire of radius 42 centimetre is bent in the form of rectangle whose sides are in the ratio 6 ratio 5 the smallest side of the rectangle is

Answer 1

HEY.......
HERE IS U R ANSWER
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CIRCUMFERENCE OF CIRCLE = 2πr
= 2 * 22/7 * 42 = 2*22*6
= 44 *6 = 264

LET THE LENGTH AND BREADTH BE 6x and 5x
so, 2( 6x + 5x) = 264
=> 11x = 134
=> x = 132 /11 = 12

SMALLER SIDE = 5x = 5*12 = 60

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Answer 2

The answer is given below :

The circumference of the circle

= 2 × π × radius

= 2 × (22/7) × 42 cm

= 264 cm

Ratio of the sides of the rectangle is = 6 : 5

Let, p be the common multiple.

Then, the sides of the rectangle are 6p cm and 5p cm.

The perimeter of the rectangle

= 2 × (sum of the sides)

= 2 × (6p + 5p) cm

= 22p cm

Now, circumference of the circle = perimeter of the rectangle

=> 264 = 22p

=> p = 12

So, the sides of the rectangle are 72 cm and 60 cm.

Thus the smallest side of the rectangle is 60 cm.

Thank you for your question.