Question

A circus artist is climbing from the ground along a rope stretched from the top of a vertical pole and tied at the ground. The height of pole is 10 m and the angle made by the rope with ground level has measure 30. Calculate the distance covered by the artist in climbing to the top of the pole.​

Answer 1

Answer:

the distance covered by the artist in climbing to the top of the pole be x

Step-by-step explanation:

Solution:- Let Ac be the length of rope =20m

and AB is the pole

Angle ACB=30 degree

Angle B = 90 degree

In triangle ABC,

Sin 30=AB/AC

1/2 =AB/20

By cross multiple

AB=10

Sin 30= opposite /hypotenuse

1/2 = 10/x

X=20

the distance covered by the artist in climbing to the top of the pole is 20 m

Answer 2

Answer:

the distance covered by the artist in climbing to the top of the pole be x

Step-by-step explanation:

Solution:- Let Ac be the length of rope =20m

and AB is the pole

Angle ACB=30 degree

Angle B = 90 degree

In triangle ABC,

Sin 30=AB/AC

1/2 =AB/20

By cross multiple

AB=10

Sin 30= opposite /hypotenuse

1/2 = 10/x

X=20

the distance covered by the artist in climbing to the top of the pole is 20 m.