A circus artist is climbing from the ground along a rope stretched from the top of a vertical pole and tied at the ground. The height of pole is 10 m and the angle made by the rope with ground level has measure 30. Calculate the distance covered by the artist in climbing to the top of the pole.
Answers
Answer:
the distance covered by the artist in climbing to the top of the pole be x
Step-by-step explanation:
Solution:- Let Ac be the length of rope =20m
and AB is the pole
Angle ACB=30 degree
Angle B = 90 degree
In triangle ABC,
Sin 30=AB/AC
1/2 =AB/20
By cross multiple
AB=10
Sin 30= opposite /hypotenuse
1/2 = 10/x
X=20
the distance covered by the artist in climbing to the top of the pole is 20 m
Answer:
the distance covered by the artist in climbing to the top of the pole be x
Step-by-step explanation:
Solution:- Let Ac be the length of rope =20m
and AB is the pole
Angle ACB=30 degree
Angle B = 90 degree
In triangle ABC,
Sin 30=AB/AC
1/2 =AB/20
By cross multiple
AB=10
Sin 30= opposite /hypotenuse
1/2 = 10/x
X=20
the distance covered by the artist in climbing to the top of the pole is 20 m.