Question

A circus tent is cylindrical up to a height of 3m and conical above it .if its diameter is 105m and the slant height of the conical part is 63m then the total area of the canvas required to make the tent is

Answer 1

$\bf \large \it \: Hey \: User!!!$

given :-

height of the cylindrical part = 3m
diameter of both cylindrical part and conical part = 105m
therefore it's radius = 105/2m = 52.5m
slant height of the conical part = 63m

we have to find the total area of the canvas required to make the tent.

for that we have to find the curved surface area of both conical and cylindrical part.

CSA of cylindrical part = 2πrh
= 2 × 22/7 × 52.5 × 3
= 6930/7
= 990m²

CSA of the conical part = πrl
= 22/7 × 52.5 × 63
= 72765
= 10395m²

therefore total curved surface area of the tent = 990 + 10395 = 11385m²

hence, 11385m² canvas is required to make the tent.

$\bf \large \it{Cheers!!!}$