Question

a circus tent is in the form of right circular cylinder and right circular cone above it. the diameter and height of cylinderical part of tent are 126 m and 5 m respectively. the total height of the tent is 21 m. find the total cost of tent if the canvas used costs ₹12/m2?

Answer 1

hello dear,
radius of tent =126/2=64m
height of cylinder h1=5m
and height of cone h2=(21-5)=16m
slant height of cone l=
$\sqrt{ ({r}^{2} + {h _{2} }^{2}) } = \sqrt{( {63}^{2} + {16}^{2}) } \\ = > \sqrt{4225} \\ = > 65m$
Total surface area of tent=curved surface area of cylinder+curved surface area of cone
=
$2\pi r h_{1} + \pi {r}l \\ = > \pi r(2 h_{1} + l) \\ = > \frac{22}{7} \times 64 \times (10 + 65) \\ = > \frac{22}{7} \times 64 \times 75 \\ = > \frac{105600}{7} \\ = > 15085.714 {m}^{2}$
And the cost of tent of canvas=15085.714×12
=>₹181028. 568
i hope it's help you dear

Answer 2

Answer:

Diameter = 126m

Radius = 126/2 = 63m

H1 = 5m

H2 = (21-6) = 16m

L = 65m

TSA = CSA Of Cylinder + CSA Of Cone

TSA = 2πrh1 + πrl

=> 14850 m^2

The cost of rent of canvas = 14850*12

=> 178200 rupees.

Thank you guys.

Thank you guys. I think this is helpful.