Question

A cirrent of 0.5A flows through a resistor of resistance 200 ohm. How much power is lost in the resistor

Answer 1

i^2 R = 200/4 = 50 watt ans

Answer 2

p=(v)2/R

we have, v=IR

O.5 X 200=100 V

P=V2/R =(100)2/200

=50W