Math, asked by akae3114, 1 year ago

A cistern 6m long and 4m wide contains water up to a depth of 1m 25cm. The total area of the wet surface is

Answers

Answered by raksha12345
21
1m = 100cm
1m +25\100 =125\100 = 1.25m
lb will be subtracted because we have to not take top layer.
area = 2(lb +bh +hl) - lb
A= 2(6*4 +4* 1.25 + 1.25*6) - 6* 4
A= 2( 24 + 5 + 7.5) - 24
A = 73 - 24
A = 49m^ 2

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