a cistern can be filled by one tap in 4 hours and another in 3 hours .how long will it take to fill if both taps are opened together
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Answered by
191
time taken by tap 1 to fill the cistern = 4h
work done in 1h = 1/4
time taken by tap 2 to fill the cistern = 3h
work done in 1 h = 1/3
one hour work of both taps = 1/4+1/3 =7/12
time taken by both taps to fill cistern =1÷7/12
=12/7 h
work done in 1h = 1/4
time taken by tap 2 to fill the cistern = 3h
work done in 1 h = 1/3
one hour work of both taps = 1/4+1/3 =7/12
time taken by both taps to fill cistern =1÷7/12
=12/7 h
Answered by
97
I hope you understand it
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