Math, asked by ravi1789, 11 months ago

A cistern can be filled by one tap in 5 hours and by another in 4 hours. How long will it take to fill if both the taps are opened simultaneously?

Answers

Answered by Anonymous
6

Answer:

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Step-by-step explanation:

Time taken by first tap to fill the cistern = 5 hours.

Work done by first tap in 1 hour = ¹/₅

Time taken by second tap to fill the cistern = 4 hours.

Work done by second tap in 1 hour = ¹/₄

Work done by (first tap + second tap) in 1 hour = (¹/₅ + ¹/₄) = ⁹/₂₀

Therefore, time taken by (first tap + second tap) to fill the cistern = 209 hours.

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Answered by sonabrainly
4

Answer:

Step-by-step explanation:

time taken by tap 1 to fill the cistern = 4h

work done in 1h = 1/4

time taken by tap 2 to fill the cistern = 3h

work done in 1 h = 1/3

one hour work of both taps = 1/4+1/3 =7/12

time taken by both taps to fill cistern =1÷7/12

=12/7 h

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