Question

A cistern can be filled by three taps A, B and C when turned on separately in 12 minutes, 10 minutes and 15 minutes respectively. If all are turned on together for 8/3 minutes and if B and C are then turned off, how much time will A alone take to fill the cistern?

Answer 1

by taking lcm of these three taps ( 60 - lcm)

then we find efficiency of each taps

that of A=5 , B=6, C = 4

A+B+C three works for 8/3 minutes

then the water filled by these three together will be 15*8/3 = 4o units

reaming water will be 60-40 = 20

and this 20 unit water will be filled by only a ( as asked in question)

then it will be 20/5=4 minutes

thts it ..thnx

Answer 2

Answer:

4 minutes

Step-by-step explanation:

hint

work done by A,B and C is 2 whole 2/3,i.e.,8/3(1/12+1/10+1/15)=2/3

remaining part

(1-2/3)=1/3