A cistern can be filled by two taps A and B in 12 hours and 16 hours respectively.
The full cistern can be emptied by a third tap C in 8 hours. If all the taps are
turned on at the same time, in how much time will the empty cistern be filled up
completely?
Answers
Answered by
0
Answer:
tap A=12h
tap B=16h
tap C=8h
therefore the 3 taps can be filled in=12×16×8
=1hr53min6sec
Answered by
0
Step-by-step explanation:
(101+81−151)×t=112012+15−8×t=112019×t=1t=19120
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