Math, asked by PriyanshuDAV, 2 months ago

A cistern can be filled by two taps A and B in 12 hours and 16 hours respectively.
The full cistern can be emptied by a third tap C in 8 hours. If all the taps are
turned on at the same time, in how much time will the empty cistern be filled up
completely?

Answers

Answered by jintyhazarika861
0

Answer:

tap A=12h

tap B=16h

tap C=8h

therefore the 3 taps can be filled in=12×16×8

=1hr53min6sec

Answered by amarjyotijyoti87
0

Step-by-step explanation:

(101+81−151)×t=112012+15−8×t=112019×t=1t=19120

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