A city supply of 15000 cubic metre of water per day treated with a chlorine dose of .5 ppm for this purpose the requirement of 25 percent bleaching powder perday would be
Answers
Amount of chlorine required/day = (15000*10^3 L/day)*(0.5*10^(-6)KG/L) = 7.5KG But bleaching powder has 25% chlorine so this must be equal to 7.5 KG Let quantity required = x KG of bleaching powder . => X *25%. = 7.5 KG X = 7.5/25% = 30 KG
Given:
Supply of water to a city = 15000 cubic metres
Chlorine dosage = 0.54 ppm
25% bleaching powder is used.
Solution:
1 cubic meter water = 1000 kg
And so, 10 cubic liters
For this city,
15,000 cubic meter per day,
So, 15,000 * 10 cubic liters per day
The amount of Chlorine per day,
15,000 * 10 cubic liters per day * 0.5 · 10 ^ ( -6 ) kilogram per liter = 7,500 · 10 ^ ( -3 ) kg
The amount of Chlorine per day = 7.5 kg
As it uses 25% of bleaching powder,
Requirement for 15000 cubic meters,
Bleaching powder required * 0.25 = 7.5 kg
Bleaching powder required = 30 kg
Hence, 30 kg of bleaching powder is required a city supply of 15000 cubic metres of water per day is treated with a chlorine dosage of 0.5 ppm.
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