Computer Science, asked by ramankumar57830, 4 months ago

A class ArrangeNum enables the user to sort any integer number according to the value of [10]
its digits.
Example: Input: 59672
Output: 25679 after sorting the digits in ascending order of their values.
Some of the members of the class are given below.
Class name
: ArrangeNum
Data members/instance variables:
n
: to store the integer number
sa
: array to store the digits of the number
Member functions/methods:
ArrangeNum( int nn) : constructor to initialize the data member n=nn
void fill_array()
: extracts the digits of the number and stores it in
the array
void arrange()
· sorts the array elements in ascending order using
any standard sorting technique
void show
• displays the original number along with the
elements of the sorted array with an appropriate
message
Define the class ArrangeNum giving details of the constructor(int), void fill_array(),
void arrange() and void show(). Define the main() function to create an object and call
the functions accordingly to enable the task.​

Answers

Answered by neelrex9999
1

Answer:

import java.util.*;

public class ArrangeNum

{

int arr[] = new int[10];

int num, i, j, t, p = 0;

void ArrangeNum(int n)

{

num = n;

}

void extract_digit()

{

while(num > 0)

{

arr[p] = num % 10;

num /= 10;

p++;

}

}

void sort()

{

for(i = 0; i < p; i++)

{

for(j = 0; j < (p-i); j++)

{

if(arr[j] < arr[j+1])

{

t = arr[j];

arr[j] = arr[j+1];

arr[j+1] = t;

}

}

}

}

void display()

{

System.out.println("Digits sorted in ascending order : ");

for(i = 0; i < p; i++)

{

System.out.print(arr[i]+" ");

}

}

public static void main(String args[])

{

Scanner in = new Scanner(System.in);

System.out.println("Enter a number : ");

int n1 = in.nextInt();

ArrangeNum obj = new ArrangeNum();

obj.NumSort(n1);

obj.extract_digit();

obj.sort();

obj.display();

}

}

Explanation:

There you go!

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