A classroom has 3 electric lamps. From a collection of 10 electric bulbs of which 6 are good, 3 are
selected at random and put in the lamps. Find the probability that all lamps are burning.
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Answer:A room has
3
electric lamps.
Out of
10
bulbs present,
6
bulbs are good.
⇒
4
bulbs are defective.
The probability that selected
3
bulbs are good
=
1
−
(Probability that selected
3
bulbs are defective)
=
1
−
4
C
3
10
C
3
=
1
−
(
4
×
3
×
2
)
(
10
×
9
×
8
)
=
1
−
1
30
=
29
30
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