a classroom whose perimeter of floor is 30 m and height is 3 m. find the area of four walls of the room.
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Total area of four walls of the classroom can be found out by multiplying the perimeter of floor and classroom height.
So the answer is 30 × 3 = 90 m².
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shadowsabers03:
As floor has two length sides, there are two walls which are attached to the length sides of the wall. Their areas should be lh each.
Likewise, there are two walls which are attached to the breadth sides of the floor. The breadth sides of the floor and the height should be the sides of those walls. Therefore, their areas will be bh each.
So there are 2 lh and 2 bh. Add them.
2lh + 2bh = 2h(l + b) = 2(l + b)h
Thnx for making me understand
2(l + b)h is the product of 2(l + b) and h, i. e., product of perimeter and height. So here we can understand that the total area of walls is the product of the perimeter of the floor and the height.
You're welcome.
This is like how we find the lateral surface area of a prism. Base perimeter x height = Lateral surface area. This is applied here.
Thank you for marking my answer as the brainliest.
no problem .
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30*3=90 this is the answer ✅
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