Question

A clay ball of mass m and speed v strikes another metal ball of same mass m, which is at rest. They stick
together after collision. The kinetic energy of the system after collision is

Answer 1

The final final kinetic energy of the system is  (mv^2) /4.

Explanation:

• By conservation of linear momentum.

Momentum before collision = momentum after collision

                                    mv = 2m v'

                                     v'  =v/2

• Now the final kinetic energy of the system will be.

K.E (f) = 1/2 mv^2

K.E(f) = (1/2) x (2m) x (v')^2

        = (mv^2) /4

Thus the final final kinetic energy of the system is  (mv^2) /4.

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