A clock face has negative charges _q _2q _3 q ........._12q fixed fixed at the position of the correspondong numerals on the dial the clock hands do not disturb the net field due to point charges at what tine does the hour hand point in the same direction in the electric field at the centre of tge dial
Answers
to calculate electric field of each point charge we need to find the component ofeach electric field towards x axis and y axis and then apply Pythagoras theoram on each component to find magnitude of the electric field.
to find the direction of electric field we need to apply tan a = Ey/Ex
that is tangent of the angle is equal to ration of component of E in y axis over x axis.
to start with you can take charge 1 that is q
now Ey= E1 sin 60, Ex= E1 cos 60 or Ey=qsin 60 and Ex=qcos 60
similarly for charge at 2 o clock we have Ey=2q sin 30 and Ex= cos 30
thus all the Ey= q sin 60 + 2q sin 30 + 3q sin 0+....
and Ex= q cos 60 + 2q cos 30 + 3q cos 0+....
calculating above and then put tan a= Ey/Ex and calculate angle a.
( fir example assume then angle a is 45 degree then it is 1:30.)