Math, asked by prataphanumant02, 7 months ago

A clock is 5 minutes slow at 4:35 p.m. on Monday and 12 minutes fast at 5:45 am the following Monday. If the clock gains uniformly,
when did it show the correct time?
A 1:46:30 p.m. on Wednesday
B 2:48:30 p.m. on Wednesday
C. 2:53:23 p.m. on Wednesday
D 2:45 a.m. on Thursday​

Answers

Answered by ananya007
2

Answer:

Wednesday 2:48:30 (b)

Answered by annarajeevlm
0

Answer:

answer option B. 2:48:30 pm on wednesday

Step-by-step explanation:

given, the watch is 5 min slow at 4:35 pm on monday and 12 minute fast at 5:45 am the following monday

time gained between  4:35 pm on monday and 5:45 am on following monday = 6 days 13 hours 10 minutes

= 157 hours 10 minutes

converting time to decimal form = 157.16 hours

time gained in 157.16 hours = 5+12 = 17 minutes

also, initially the clock was 5 minute slow than the correct time

this 5 minute is gained in \frac{157.16*5}{17} = 46.22 hours

         = 46 hours 13 minutes 12 seconds

5 minute is gained in = 1 day 22 hours 13 minutes 12 seconds

thus, the watch shows the correct time 2:48:12  pm on wednesday

answer option B. 2:48:30 pm on wednesday

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