Question

The diagonal of the rhombus is in the ratio of 3:4. If the longer diagonal is 12 cm, then find the area of the rhombus

Answer 1

Answer:

I am not sure but it can be

Step-by-step explanation:

If the two legs are in a 3:4 ratio, this is a 3–4–5 pythagorean triple.

Since the Hypotenuse is 40, that is 5 x 8. So the sides will measure 3 x 8 (24) and 4 x 8 (32).

These sides of the right triangle are half the entire diagonal, so the diagonals are 48 and 64.

The area of a rhombus can be found by the formula (1/2)(D1)(D2) = (1/2)(48)(64) = 1536.

Answer 2

Step-by-step explanation:

S O L U T I O N

• Diagonals of a rhombus are in the ratio of 3:4. And, the longer diagonal is 12 cm.

• We've to find out the area of the rhombus.

let's consider that smaller & longer diagonal of the rhombus be 3x & 4x.

⠀⠀⠀⠀⠀⠀ ━━━━━━━━━━━━━━━━━━⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀

$:\implies\sf 4x = 12 \\\\\\:\implies\sf x = \cancel\dfrac{12}{4} \\\\\\:\implies\sf\pink{ x = 3}\\\\\\:\implies\sf 3x \qquad\qquad \bigg\lgroup\bf Smaller \ Diagonal \bigg\rgroup \\\\\\:\implies\sf 3 \times 3\\\\\\:\implies\boxed{\bf{\blue{Diagonal_{(smaller)} = 9 \: cm}}}\\\\\\:\implies\sf 4x \qquad\qquad \bigg\lgroup\bf Longer \ Diagonal \bigg\rgroup\\\\\\:\implies\sf 4 \times 3\\\\\\:\implies\boxed{\bf{\blue{Diagonal_{(longer)} = 12 \: cm}}}$

⠀By using the formula,

⠀⠀⠀⠀⠀⠀ ⠀⠀⠀

$\star\ \boxed{\purple{\sf{Area_{(rhombus)} = \frac{1}{2} \times (d_1) \times (d_2)}}}$

$\bf{Diagonals}\begin{cases}\sf{d_{1} = 9 \ cm}\\\sf{d_2 = 12 \ cm}\end{cases}$

Substituting values in the formula,

⠀⠀⠀⠀⠀ ⠀⠀⠀

$:\implies\sf Area_{(rhombus)} = \dfrac{1}{\cancel{ \: 2}} \times 9 \times \cancel{12} \\\\\\:\implies\sf Area_{(rhombus)} = 9 \times 6 \\\\\\:\implies\boxed{\frak {Area_{(rhombus)} = 54 \ cm^2}}$

⠀⠀⠀⠀⠀⠀

$\therefore\:\underline{\sf{Area \: of \: the \: rhombus \: is \: \bf{54 \: cm^2.}}}$