Question

A clock is showing 4 O'clock. If hour needle moves an angle of
90°, then it will show
O'clock.
​

Answer 1

Answer:

Explanation:angle b/w 4o'clock-5 o'clock is =30degree and 5-6=30degree,6-7 =30Degree so 30+30+30=90degree so tym will be 7 O' clock

Answer 2

Answer:

If the hour needle moves by an angle of 90°, then it will show 7'O'clock

Explanation:

Given:

Initial time=4'O'clock

Angle=90°

To find: Final time=?

Solution:

We know that,

In a clock 360°=12 hours

Therefore, 1 hour can be calculated as

$\frac{360}{12}=30$°

The hours corresponding to 90° can be calculated by dividing 90 by 30.

$\frac{90}{30}=3 hours$

Adding 3 hours to the initial time to get the final time.

Final time=4+3=7

The final time is 7'O'clock

Thus, If the hour needle moves by an angle of 90°, then it will show 7'O'clock