Question

A closed container contains 56 gram of N2 and 20 gram of H2 if partial pressure of N2 is 1 ATM then find total pressure of the gas molecules in the container​

Answer 1

total pressure of the gas molecules in the container is 6atm.

mass of N2 gas = 56gram

molecular mass of N2 = 28 g/mol

so, no of moles of N2 = 56/28 = 2 mol

similarly, mass of H2 gas = 20g

no of moles of H2 = 20/2 = 10 mol

now, mole fraction of N2 = 2/(2 + 10) = 2/12 = 1/6

and mole fraction of H2 = 10/(2 + 10) = 5/6

given,

partial pressure of N2 = 1atm

let total pressure of the gas molecules in the container is P

so, Partial pressure of N2 = mole fraction of N2 × total pressure

⇒1 = 1/6 × P

⇒P = 6 atm

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