Question

A closed cure encircles several conductors. The line integral intB.dI around this curve is 3.83xx10^-7T-m a. What is the net current in the conductors? b. If you were to integrate aroundthe curve in the opposite direction, what would be the value of the line integral?

Answer 1

Given:

• Line integral = $3.83 * 10^{-7} T m$

To find:

• Net current in the conductor.
• Value of line integral if integrated around the curve in opposite direction.

Answer:

•     Line integral = μ₀ I    

       ⇒  $3.83 * 10^{-7} T m$  = $4\pi * 10^{-7}$ I

       ⇒ I = 0.3 A

• Value of line integral if integrated around the curve in opposite direction

          = - $3.83 * 10^{-7} T m$