An n - p- n transistor is connected in common - emitter configuraration in which collector supply is 8 V and the voltage drop across the load resistance of 800 Omega connected in the collector circuit is 0.8 V . If current amplification factor is 25 , determine collector - emitter voltage and base current . If the internal resistance of the transistor is 200 Omega , calculate the voltage gain and the power gain.
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The voltage gain = 4, Current gain = 0.96 and Power gain = 3.84 respectively.
Explanation:
Given:
- Rc = 800Ω,
- V L = 0.8 V
- R B = 192 Ω
Current amplification factor = 0.96
Hence,
I c / I B = 0.96
β = 0.96
V E = 0 ⟹V B =0
Collector current is given by I C = V L /R c = 0.8 / 800 = 10^−3 A
Base current is given by, I B = I C / β = 10^−3 / 0.96 A
Voltage Gain, A v = V out / V in = V L / V BB = 0.2 / 0.8 = 4
Current Gain, I A = I out / I in = Ic / IB = β = 0.96
Power Gain, A P = AvAI = 4 x 0.96 = 3.84
Hence the voltage gain = 4, Current gain = 0.96 and Power gain = 3.84 respectively.
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