Math, asked by preethinigam, 1 year ago

a closed cylindrical tank of height 1.4 metres and radius of the base is 56 cm is made up of thick metal sheet how much metal sheet is required Express in square metres​

Answers

Answered by VishalSharma01
152

Answer:

Step-by-step explanation:

Given :-

Height of the cylinder, h = 1.4 m

Radius of the base, r = 56 cm = 56/100 = 0.56 m

To Find :-

Metal sheet is required.

Formula to be used :-

Total metal sheet required = Total Surface Area of the cylinder.

That is 2πr(r+h).

Solution :-

Putting all the values, we get

Total metal sheet required = Total Surface Area of the cylinder.

Total metal sheet required = 2πr(r+h)

Total metal sheet required = 2 × 22/7 × 0.56(0.56 + 1.4)

Total metal sheet required = 2 × 22 × 0.08 × 1.96

Total metal sheet required = 6.8992 m²

Hence, 6.8992 m² Metal sheet is required.

Answered by Anonymous
61

Solution:

Dimensions of closed cylindrical tank:

\implies Height (h) = \sf{1.4\:m}

\implies Radius (r) = \sf{56\:cm = \frac{56}{100}\:m = 0.56\:m}

And:

Metal sheet required = Total surface area of the cylindrical tank

Formula to be used:

\implies \huge{\boxed{\sf{2  \pi  r(r+h)}}}

Now:

Substituting the values we get:

\implies \sf{2 \times  \frac{22}{7}  \times 0.56(0.56 + 1.4)}

\implies \sf{2 \times 22 \times 0.08 \times 1.96}

\implies \sf{44 \times 0.08 \times 1.96}

\implies \sf{6.8992 \: square \: meters}

Therefore:

Metal sheet required: \sf{6.8992\:m^{2}}

Similar questions