Question

A closed rectangular box has inner dimensions 34cm×24cm×20cm. find the area of the paper requires to cover its inner surface

Answer 1

l=34cm,b=24cm,h=20cm
inner surface area=2(34×24+24×20+20×30)
=2(816+480+600)
=2(1896)
=3792
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Answer 2

The area of the paper requires to cover its inner surface is 3952 sq.cm.

Step-by-step explanation:

Length of box = 34 cm

Breadth of box = 24 cm

Height of box = 20 cm

Total surface area of box = 2(lb+bh+hl)

Total surface area of box = $2(34 \times 24 + 24 \times 20 + 20 \times 34)$

Total surface area of box = $3952 cm^2$

Hence the area of the paper requires to cover its inner surface is 3952 sq.cm.

#Learn more:

A closed rectangular wooden box has inner dimension 90cm by 80cm by 70cm compute its capacity and the area of the tin foil needed to line its inner surface

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