A closed vessel contains He and
03 at a
pressure of P atm. The ratio of He
and O atoms
is 1:1. If He is removed from the
vessel, the
pressure of the system will reduce
to
0.5 P.
0.75 P.
0.25 P.
0.33 P
Answers
Answered by
0
Answer:
0.5 P
Explanation:
He and O3 has equal number of molecules
So, mole fraction is also equal of each component
Partial pressure= 1/2 of total pressure
So, when we remove the He the partial pressure of He is removed.
So, P goes to P/2⇒0.5Patm
thanks
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