a closed vessel contains Ozone dinitrogen and I hydrogen gas and exert a pressure of p if sample consists of equal number of atoms of oxygen nitrogen and hydrogen then what will be the pressure when Ozone is removed
Answers
Answer:
Explanation:
in answering this question, we are going to be assuming ideal gas behavior where PV is equality and our t. Now looking at the information that we've been given this value of end, this is the total number of moles and the total number of malls are the number of moles of oxygen plus the number of moles off nitrogen. And this is equal to set up 1322 plus one point 5 3. And this gives us a number of malls That is equal to 1.8520. Now that we have this number of moles, we can then determine the pressure, P S N R A T divided by the volume. And if we are using an r. 0.08206 atmosphere later, pair moral kelvin, we need to make sure that the temperature is in kelvin and the volume is in letters. Therefore we've got p being equal to the number of moles which is 1.8 52 Multiplied by and 7.78, multiplied by the temperature in Kelvin which is 373 Divided by the volume in L, which is 3.2. And this gives us a pressure that is equal to 1 7.6 and the units are in atmosphere