A closed wooden box is in the form of cuboid.Its length,breath.and height are 6m,1.5m and 300cm respectively.Find the T.S.A and cost of painting its entire outer surface at the rate of rupee 50 per m^2
Please give cotrect answer otherwise I will report
and for proper I will mark as brainlist
Answers
(i)
Here, l = 12 cm, b = 8 cm, h = 4.5 cm
Volume of the cuboid = l×b×h
=(12×8×4.5) cm3= 432 cm3
Total Surface area = 2(lb + lh+ bh)
=2(12×8 + 12×4.5 +8×4.5) cm2=2(96 +54 + 36) cm2=2× 186 cm2=372 cm 2
Lateral surface area = 2(l+b)×h
=[2(12+8)×4.5] cm2=[2(20)×4.5] cm2=40×4.5 cm2=180 cm2
(ii)
Here, l = 26 m; b = 14 m; h =6.5 m
Volume of the cuboid = l×b×h
=(26×14×6.5)m3=2366 m3
Total surface area = 2(lb + lh+ bh)
=2(26×14+26×6.5+6.5×14) m2=2(364+169+91) m2=2×624 m2=1248 m2
Lateral surface area = 2(l+b)×h
=[2(26+14)×6.5] m2=[2×40×6.5] m2=520 m2
(iii)
Here, l = 15 m; b = 6 m; h = 5 dm = 0.5 m
Volume of the cuboid = l×b×h
=(15×6×0.5) m3=45 m3
Total surface area = 2(lb + lh+ bh)
=2(15×6+15×0.5+6×0.5) m2=2(90+7.5 +3) m2=2×100.5 m2= 201m2
Lateral surface area = 2(l+b)×h
=[2(15+6)×0.5] m2=[2×21×0.5] m2=21 m2
(iv)
Here, l = 24 m; b = 25 cm = 0.25 m; h =6 m
Volume of the cuboid = l×b×h
=(24×0.25×6) m3=36 m3
Total Surface area = 2(lb + lh+ bh)
=2(24×0.25 +24×6 +0.25×6) m2=2(6+144 + 1.5) m2=2×151.5 m2=303 m2
Lateral surface area = 2(l+b)×h
=[2(24+0.25)×6] m2=[2×24.25×6] m2=291 m2