Question

a closely wound flat circular coil of 25 turns of wire has diameter of 10cm and carries a current of 4ampere. Determined the magnetic field at the center of the coil. ​

Answer 1

Answer:

dmfkxkd no

Explanation:

bxbjfuvcij TV v

Answer 2

Answer:

hey mate

Explanation:

1

Secondary School Physics 5 points

A closely wound flat circular coil of 25 turns of

wire has diameter of 10 cm and carries a current

of 4 ampere. Determine the magnetic flux density

at the centre of the coil :-

Ask for details Follow Report by Anonymousman007 24.09.2019

Answers

anjali30703

anjali30703 Genius

Answer:

10^-5 Weber is the answer...

3.4

5 votes

THANKS

7

Comments Report

muscardinus Ambitious

Magnetic flux density, \phi=3.94\times 10^{-7}\ Wb

Explanation:

it is given that,

Number of turns of the coil, N = 25

Diameter of the wire, d = 10 cm

Radius, r = 5 cm = 0.05 m

Current, I = 4 A

The magnetic field at the center of the coil is given by :

B=\dfrac{\mu_oI}{2r}

B=\dfrac{4\pi \times 10^{-7}\times 4}{2\times 0.05}

B=5.02\times 10^{-5}\ T

Let \phi is the magnetic flux density at the center of the coil. It is given by :

\phi=BA

\phi=\pi r^2 B

\phi=\pi (0.05)^2 \times 5.02\times 10^{-5}

\phi=3.94\times 10^{-7}\ Wb

So, the magnetic flux density at the center of the coil is 3.94\times 10^{-7}\ Wb. Hence, this is the required solution.

Learn more :

Magnetic flux density

brainly.in/question/11705809