A closely wound solenoid of 500 turns and area
of cross section 4 x 10 m carries a current of
2A. Calculate the magnetic moment of solenoid.
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1
Answer:
40000 Am²
Explanation:
N = 500 turns
I = 2A
A = 4 m x 10 m = 40 m²
Magnetic moment M = N × I × A
= 500 × 2 × 40
= 40 × 10³ Am²
= 40000 Am²
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