a club consist of member whose age are in A.p the common difference being 4th months.if the youngest member of the club is 8years old and the sum if all the members in 168 year find the total number of members in the club
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hii dear !!
solution:
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➡ATQ
a=8
d=4
sum of all terms=168
now,
let the no. of terms be n then,
Sn = n/2×{2a+(n-1)d}=168
=>n{16+(n-1)4}=84
=>16n+4n^2-4n=84
=>4n^2+12n-84=0
=>n^2+3n-21=0
solution:
==================================
➡ATQ
a=8
d=4
sum of all terms=168
now,
let the no. of terms be n then,
Sn = n/2×{2a+(n-1)d}=168
=>n{16+(n-1)4}=84
=>16n+4n^2-4n=84
=>4n^2+12n-84=0
=>n^2+3n-21=0
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