Question

A 'cm' cube has its upper face is placed by 0.1cm by tangential force of 0.8 dyne.caculatebshear modulus of the cube??

Answer 1

length of the cube (l) = 1cm = 0.01m
shear force(F) = 0.8 dyne = 8*10^-6 N
area(A) = 1 cm² = 10^-4 m²
shear stress = F/A = 8*10^-2 N/m² = 0.08 N/m²
Δl = 0.1 cm = 0.001m
l = 1cm = 0.01m
shearstrain = Δl/l = 0.001/0.01 = 0.1

shear modulus(G) = shear stress/shear strain = 0.08/0.1 = 0.8 N/m²