What should be the pressure on a liter of water be change to compress it by 0.15%?
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Bulk modulus of water(B) = 2.2*10^9 Pa
change in volume = 0.15%
or (ΔV/V) = 0.15% = 0.15/100 = 15/10000
B = ΔP / (ΔV/V) = ΔP/(15/10000)
⇒(2.2*10^9)*(15/10000) = ΔP
⇒2.2*15*10^5 = ΔP
⇒ΔP = 3.3*10^6 Pa
⇒ΔP = 3.3 MPa (MPa - million pascal)
So change in pressure is 3.3 MPa.
change in volume = 0.15%
or (ΔV/V) = 0.15% = 0.15/100 = 15/10000
B = ΔP / (ΔV/V) = ΔP/(15/10000)
⇒(2.2*10^9)*(15/10000) = ΔP
⇒2.2*15*10^5 = ΔP
⇒ΔP = 3.3*10^6 Pa
⇒ΔP = 3.3 MPa (MPa - million pascal)
So change in pressure is 3.3 MPa.
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