Question

A cobex lens of focal length 6 cm is held 4 cm from a newspaper which has print 0.5cm high .By calculation of the image produced​

Answer 1

Explanation:

Given:

Focal length, f = 6 cm

Object distance, u = -4 cm

Size of the object, h = 0.5 cm

Applying lens formula, we get:

1/v -1/u = 1/f

or, 1/v = 1/f + 1/u

= 1/6 + 1/(-4) = -1/12

or, image distance, v = -12 cm

Applying magnification formula, we get:

m = v/u = h'/h

or, m = (-12)/(-4) = h'/0.5

or,  3 = h'/0.5

or,      h, =3×0.5

Size of the image, h' = 1.5 cm

Therefore, the height of the image is 1.5 cm. The value of magnification is positive; therefore, the image is virtual, erect and three times magnified.

Hope This will help you

❤❤❤

Mark me as brainliest if possible