Chemistry, asked by airanvaibhav2903, 11 months ago

A cocktail rumpumpum comprises 20% alcohol and 10% orange juice. Another cocktail lskiuski is a concoction of rumpumpum and terimeri in the ratio 3:5. If 200 ml of lskiuski comprises 17.5% alcohol, what is the percentage of alcohol in terimeri?

Answers

Answered by sourya1794
29

Explanation:

When creating a new cocktail, balance is always important. A common rookie mistake is to make a cocktail that has the alcohol content way out of proportion. You know, the one that should actually have the flammable symbol on the side of the glass. Five ounces of Everclear (95% ABV), one-ounce orange juice! The idea being that; it may not taste good but it will get you “wasted”. Well, we’ve all done that and realized that there are better ways to enjoy the benefits of alcohol. The best way is in a well-balanced cocktail.

The best example of a balanced drink is wine. It has a moderate alcohol content and the sweet and sour balance each other out nicely. The alcohol content of a standard glass of wine is around 12% with some wines approaching 14%. Some ports and sherry have alcohol content in the 17% to 20% range, and still taste very good, usually because the sugar content is higher. Again, it’s all about balance in drinks.

Back in the golden age of cocktails, mixologists thought about how they created their cocktails, including the alcohol content of the finished drink. There ended up being a proportions formula for drinks that looked like this:

1 part sour, 2 parts sweet, 3 parts strong and 4 parts weak

If we create a hypothetical cocktail based on these proportions it would like this:

45 ml (3 Parts) Rum (40% ABV)

30 ml (2 Parts) Pineapple Juice

15 ml (1 Part ) Lime Juice

60 ml (4 Parts) Ice / Water

Sum = 150 ml

The total volume of this drink is 150 ml (5 oz) and the alcohol percentage is 12%. It seems that 12% seems to be the right amount of alcohol for a cocktail and those old timers knew it.

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