Question

A code consists of two digit numbers chosen from 00-99 (i.e 00, 01, 02…..99) followed by two different letters of the alphabet. What is the probability that the code is 43MZ?A code consists of two digit numbers chosen from 00-99 (i.e 00, 01, 02…..99) followed by two different letters of the alphabet. What is the probability that the code is 43MZ?

Answer 1

Answer:

Out of the numbers 00,01,02,...,99, those numbers the product of whose digits is 18 are 29,36,63,92.

∴P(E)=

100

4

=

25

1

⇒P(

E

)=

25

24

The probability that in selecting form numbers the events E occurs at least three times

=

4

C

1

(

25

1

)

3

25

24

+

4

C

4

(

25

1

)

4

=

(25)

4

4×24

+

(25)

4

1

=

(25)

4

97

Explanation:

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