A codidate who gets 36 marks in an exam fail by 24 marks but another condidate who get 43% marks get 18 more marks than the minimum pass marks .find the maxium marks and the percentage of pass marks
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Answered by
0
78 out of what is 43%?
78 out of X is 43%
Equation: Y/X = P%
Solving our equation for X
X = Y/P%
X = 78/43%
Converting percent to decimal:
p = 43%/100 = 0.43
X = 78/0.43
X = 181.3953
78 out of X is 43%
Equation: Y/X = P%
Solving our equation for X
X = Y/P%
X = 78/43%
Converting percent to decimal:
p = 43%/100 = 0.43
X = 78/0.43
X = 181.3953
Answered by
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In any case: 2 equations will be formed for this.
Assuming 't' is the total marks & 'p' being the passing marks.
(1) 0.20t = p -10
(2) 0.42t = 1.12p
Solving for t yields, t = 560/9.8 , which is approx. 57 or 58. Also, p = approx. 21. ..
Please mark it as brainiest answer ...............
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