Question

A coffee mixture contains beans that sell for $0.08 per pound and $0.32 per pound. If 110 pounds of beans create a mixture that sells for $0.27 per pound, to the nearest tenth of a pound, how much of each bean is used in the mixture? Model the scenario with an equation and solve. Use complete sentences to explain whether or not your solution is reasonable.

Answer 1

Answer:

Answer by Boreal(13358) About Me  (Show Source):

You can put this solution on YOUR website!

bean A is 0.08/pound

bean B is 0.32/pound

A+B=110

.08A+0.32(B)=29.7 (that comes from the mixture of 110 pounds at 0.27/pound)

A=110-B

0.08(110-B)+0.32B=29.7

 

8.8-0.08B+0.32B=29.7

0.24B=20.9

B=87.1 [email protected]=27.87

A=22.9 [email protected]=1.83

That is 110 pounds with a dollar value of $29.70, which is $0.27 per pound.

This is reasonable if one can weigh beans to the nearest tenth of a pound.

Step-by-step explanation: