A coil area .05 800 turn . It is placef in magnetic field 4 ×10^-5 rotated by 90° in .1 sec . Avd emf
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emf e is given by ∆phi / ∆t
Let initially theta be 0° then flux will be 0°. theta is the angle between m.f. and coil.
phi1 = 0
phi2 = NBASin (theta) = NBA
phi2 = 1.6 * 10^-3
or e = 1.6 * 10^-3
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