A coil had 100 turns. The radius of each turn is
20 cm. An iron rod (u = 35) is introduced inside
it. Find the magnetic field at the centre when current
in coil is 2 A.
(1) 0.022 T
(2) 0.22 T
(3) 0.33 T
(4) 0.033 T
Answers
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Answer:
n=100, r = 20 cm = 0.2 m, μr=
μ
0
μ
=35
i=2A
⇒μ=35μ
0
μ=35×4π×10
−7
m k.s unit
Field at certen will
be B=
2r
μi
×m
B=
2×0.2
35×4π×10
−7
×2×100
⇒B=.0219≈.022 Tesla
m.k.s unit.
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