Question

A coil has inductance of5 mh in it . Current changes from 0.1A to 4.1Ain 0.5 seccal induce emf

Answer 1

Answer:

-0.04V

Explanation:

L =

$5 \times {10}^{ - 3} h$

dI/dt = (4.1-0.4)/0.5 = 40/5 =8A/s

E = -L * dI/dt

$e = - 5 \times {10}^{ - 3} \times 8$

E = 0.04V