A coil having 500 square loops each of side 10 cm is placed normal to a magnetic flux which increases at the rate of 1.0 tesla/second. The induced e.m.f. in volts is(a) 0.1(b) 0.5(c) 1(d) 5
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answer option (d) 5V
explanation : number of turns = 500
cross sectional area of square coil = 10² cm² = 10^-2 m²
magnetic field normal to the square coil changes at the rate, [tex]\frac{dB}{dt} = 1 T/s
so, the induced emf , e = - NA × dB/dt
where N denotes number of turns , A denotes cross sectional area of coil and dB/dt is the rate of change of magnetic field.
= - 500 × 10^-2 × 1 V
= - 5 V
hence, induced emf in volts will be 5 V
explanation : number of turns = 500
cross sectional area of square coil = 10² cm² = 10^-2 m²
magnetic field normal to the square coil changes at the rate, [tex]\frac{dB}{dt} = 1 T/s
so, the induced emf , e = - NA × dB/dt
where N denotes number of turns , A denotes cross sectional area of coil and dB/dt is the rate of change of magnetic field.
= - 500 × 10^-2 × 1 V
= - 5 V
hence, induced emf in volts will be 5 V
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