Physics, asked by Tejbhan7891, 1 year ago

The magnetic flux linked with a coil is given by an equation ∅ (in webers) = 8t²+3t+5. The induced e.m.f. in the coil at the fourth second will be
(a) 16 units(b) 39 units(c) 67 units(d) 145 units

Answers

Answered by abhi178
4
answer : option (c) 67 units

explanation : magnetic flux linked with the coil is given by, \phi=8t^2+3t+5

we know, induced emf is the negative of rate of change of magnetic flux with respect to time.
e.g., \xi_{in}=-\frac{d\phi}{dt}

so, first of all, differentiate magnetic flux with with respect to time,

e.g., \frac{d\phi}{dt}=16t+3

at t = 4, \frac{d\phi}{dt}=16\times4+3=67

so, induced emf = - \frac{d\phi}{dt} at t = 4
= -67 units

hence, magnitude of induced emf in the coil at the fourth second will be 67 units.

no4: Good job
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